[Event "Baltische Schachblätter"]
[Site "?"]
[Date "1908.??.??"]
[Round "?"]
[White "Behting, AA."]
[Black "White to play and draw"]
[Result "1/2-1/2"]
[Annotator "Frederic Friedel/MB"]
[SetUp "1"]
[FEN "8/8/7p/3KNN1k/2p4p/8/3P2p1/8 w - - 0 1"]
[PlyCount "5"]
[EventDate "1908.??.??"]
[SourceDate "2003.10.01"]

{CSS 4+5/1984 pp.30-33} 1. Kc6 $3 (1. Nxh4 $2 Kxh4 2. Nf3+ Kg3 3. Ng1 (3. Ke4
Kf2 4. Kf4 h5 5. Ng5 g1=Q 6. Nh3+ Kg2 7. Nxg1 Kxg1 $19) 3... h5 $1 4. Ke4 (4.
Kd4 Kh2 5. Nf3+ Kh1 6. Kxc4 h4 7. d4 h3 8. d5 h2 9. d6 g1=Q 10. Nxg1 hxg1=Q $19
) 4... Kf2 5. Nh3+ Kf1 6. Kf4 g1=Q 7. Nxg1 Kxg1 $19) (1. Nf3 $2 h3 2. N5h4 (2.
Ke4 h2 3. Ng3+ Kg4 4. Nxh2+ Kxg3 5. Nf3 Kf2 $19 {z.B.} 6. Kf4 g1=Q 7. Nxg1 Kxg1
8. Ke5 h5 9. Kd5 h4 10. Kxc4 h3 11. d4) 2... h2 3. Nxg2 h1=Q 4. Ngh4 {and now
e.g.} Qf1 5. Ke4 Qf2 6. Kd5 Qe2 7. Kd4 Kg4 8. Kd5 h5 9. Kd4 Qxf3 10. Nxf3 Kxf3
$19) (1. Ke4 $2 g1=Q 2. Nxh4 Qb1+ $19) (1. Ng7+ $2 Kg5 2. Nf3+ Kg4 (2... Kf4 3.
Ng1 Kg4 4. Ne6 $1 h3 5. Nxh3 Kxh3 6. Nf4+ Kg3 7. Nxg2 Kxg2 8. Kxc4 $11) 3. Ne5+
(3. Ng1 h3 $19) ({Nunn: After} 3. Ke4 h3 4. Nf5 g1=Q 5. Nxg1 h2 6. Nxh6+ Kh5 (
6... Kg3 7. Nf5+ Kg2 8. Nf3 h1=Q 9. N5d4 {is very similar}) 7. Nf3 h1=Q 8. Nf5
Kg4 9. Ne3+ Kg3 10. Nf5+ Kf2 11. N5d4 {we reach an interesting position with
Q+P vs 2N+P. Since in general positions with Q v 2N are drawn, if Black is to
win he has to make progress without allowing an exchange of pawns. It isn't
obvious how he can do this, although there are various attempts which come
close to succeeding.} Kg2 {MB: this is the quickest way to force a winning
6-man endgame readily checked with online tablebases.} 12. Kd5 (12. Ke3 Qa1 13.
Nh4+ (13. Ke4 Kg3 14. Ne5 Qh1+ 15. Nef3 (15. Ndf3 Qb1+ 16. Ke3 Qf5 17. Ke2 c3
18. dxc3 Qe4+ $19) 15... Qh7+ 16. Ke3 (16. Ke5 Qb7 17. Ke6 Kf4 18. Kd6 Qb4+ 19.
Kd5 Qa5+ 20. Kxc4 (20. Kd6 c3 21. dxc3 Ke4) 20... Ke4 $19) (16. Nf5+ Kf2 17.
Kf4 (17. Ng5 Qc7 18. Nd4 Qa5 19. Ngf3 Qa8+ 20. Kf5 (20. Kf4 Qd5 21. Kg4 Qe4+
22. Kg5 Qxf3) 20... c3 21. dxc3 Qc8+ $19) 17... Qd7 18. Ne3 Qd6+ 19. Ke4 (19.
Ne5 Qxd2 $19) 19... Qg6+ 20. Nf5 (20. Kf4 Qg3+ $19) 20... Qg4+ $19) 16... Qd3#)
13... Kg3 14. Nhf5+ Kg4 15. Ke2 (15. Ke4 Qh1+ $1 16. Ke5 Qh2+ $1 17. Ke4 Qf4+
18. Kd5 Qxd2 $19) 15... Kf4 16. Nc2 Qh1 17. Nfe3 c3 18. d4 (18. dxc3 Ke4 $1 $19
) 18... Ke4 19. Nd1 Qf3+ 20. Ke1 Qg3+ 21. Kf1 Qd3+) 12... Kg3 13. Ke4 (13. Kxc4
Kf4 $19) 13... Qh7+ {and further as in variation B1a above}) 3... Kf4 4. Nh5+
Kf5 $19) (1. Ng3+ $2 hxg3 2. Nf3 Kg4 3. Ke4 h5 4. Ne5+ Kh3 5. Nf3 h4 6. Kf4 (6.
Kf5 g1=Q 7. Nxg1+ Kg2 8. Ne2 Kf2 9. Nf4 g2 10. Nh3+ Kg3 11. Ng1 h3 $19) 6...
g1=Q 7. Nxg1+ Kg2 8. Nf3 h3 $19) 1... g1=Q (1... h3 2. Ng3+ Kh4 (2... Kg5 3.
Ne2 Kh4 (3... Kf5 4. Nf3 Ke4 5. Neg1 $11) 4. Nf3+ Kg4 5. Nh2+ {and at least a
draw.}) 3. Ne2 h2 4. Nf3+ Kh3 5. Nxh2 $1 (5. Neg1+ hxg1=Q 6. Nxg1+ Kh2 7. Ne2
g1=Q 8. Nxg1 Kxg1 $19) 5... Kxh2 6. Kd5 $10 g1=Q 7. Nxg1 Kxg1 8. Kxc4 h5 9. d4)
(1... Kg5 2. Nf3+ Kxf5 3. Nxh4+ Ke4 4. Nxg2 Kd3 5. Kd5 $11) 2. Nxh4 $1 Qh1+ {
Black has only this one check, which is the reason that 1.Kc6!! was required
in the starting position.} 3. Nhf3 1/2-1/2

