MNb wrote on 03/06/07 at 20:44:12:
Maybe everybody is baffled by 10.0-0-0, as there is a bishop on c1 yet.
6.Nc3/9.Bf4 0-0 10.0-0-0 d5 11.cxd5 Nxd5 12.Nxd5 cxd5 13.Rxd5 (13.Bxd5 Nb4) Be6 14.Rd2 (iso 14.Rb5) Rac8+ 15.Kb1 Nc5 16.Nh3 and maybe Black's compensation is not entirely enough?
Well, it looks to me as if 16. Nh3 Bf5+ 17. Ka1 Bf6 leaves Black with some comp. Whether quite enough, I am not sure, but it looks pretty hopeful:
18. Be3 Na4.
18. Rhd1 Ne4 19. Bxe4 Bxe4 and I suspect that Black's activity and two bishops will be enough to hold the balance.
Critical is 18. f3 Rfd8 e.g. 19. e4 Rxd2 20. Bxd2 Na4 21. Kb1 Be6 and now:
(1) 22. b3 Rd8 23. Kc2 Rc8+ 24. Kd1 Rd8 25. Ke2 Nc6+ 26. Bxc6 Bxc6 27. Rd1 Rxd1 28. Kxd1 and now 28...Bxh3 appears to draw by virtue of opposite colored bishops.
(2) 22. Bc1 Rc6 23. Nf2 (23. Nf4 Bc4) 23...Rd6 24. Nd1 Bc4 =.
But instead of 21. Kb1, better is 21. exf5 Rc2 (I hoped this would equalize, but it doesn't) 22. Rc1 Rxd2 23. Rc8+ Bd8 24. Kb1 Kf8 25. b3 Rxg2 and Black is struggling a little. Whether he can draw, I'm not sure. Nor do I like Blacks alternatives to 20...Na4 very much. So perhaps this deals with 10...d5.
It would be nice if a stronger player would supply his judgement here.