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Very Hot Topic (More than 25 Replies) Refutation of the Ryder Gambit (Read 61224 times)
Gambit
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Re: Refutation of the Ryder Gambit
Reply #3 - 03/09/10 at 05:48:25
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I only play the Ryder Gambit in blitz games. The reason for this is because I am more familiar with the 5 Nxf3 lines than with 5 Qxf3. It is my opinion that the Ryder is far more riskier than the BDG. That said, it still has practical chances in over-the-board tournaments. This is because people won't have the advantage of computer assistance to help them.
  
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MNb
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Re: Refutation of the Ryder Gambit
Reply #2 - 03/09/10 at 01:46:18
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Believe me or not, but when I played the Ryder Gambit some 15 years ago (only OTB) I found that there were a few points not entirely clear after 6...Qg4.
The line that bothered me most was 6...Qh4+ 7.g3 Qb4 (an improvement on 6...Qb4) 8.0-0-0 c6 and as White can't play 9.Qg3 Black is better.
  

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kylemeister
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Re: Refutation of the Ryder Gambit
Reply #1 - 03/09/10 at 00:29:59
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Pachman, Gallagher and Rizzitano have given 6...Qg4 7. Qf2 e5 as clearly better for Black.
  
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Refutation of the Ryder Gambit
03/08/10 at 23:19:54
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Let's get a bit generous and offer two pawns.
I own a copy of Diemer's book "Vom ersten Zug auf Matt". It largely deals with a gambit idea Diemer credits to a Dr. Ryder.

1.d4 d5 2.e4 dxe4 3.Nc3 Nf6 4.f3 exf3 5.Qxf3

From theoretical point of view I can't believe that this is good anyhow. But Diemer played it quite regularly. And on practical basis it worked.
The question to me is: What ist the best way to defend Black's case in this variation? Does White get enough practical chances (not theoretical), or is there a clear refutation - discovered by, say, Rybka?
Can Black simply take ond d4 (5...Qxd4) and how does he proceed after 6.Be3?
Are other continuations - 5...c6, 5...e6, 5...g6, 5...Nc6, 5...Nbd7 - more to the point?

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