SWJediknight wrote on 04/29/09 at 19:28:23:
Re. the 8.0-0 Nxd4 9.Kh1 c6 10.Nxd4 Qxd4 11.Qe1 Qc5:
A) Stefan Bucker's suggestion of 12.Bh4 Qh5 13.Qg3 Qg4 14.Qe1 0-0 15.h3 Qh5 16.Ne4 Nd5 17.Bxe7 Nxe7 18.Nd6 looks like it gives some compensation for two pawns- quite a good blitz try, though objectively it looks -/+ to me.
B) 12.Qh4 h6 13.Bxf6 does indeed look refuted by 13...gxf6!. An alternative is 13.Bd2 Qh5 14.Qg3 which again looks -/+.
C) Perhaps the alternative 10.Qe1 (instead of 10.Nxd4) is worthy of consideration. 10...Nxf3 11.Rxf3 Nd5 12.Bxe7 Qxe7 13.Qe5 gives White a bit of play. However, I think all lines lead to =+ at best for White, and probably worse.
As for 1.e4 c6 2.d4 d5 3.Nc3 dxe4 4.Bc4 Nf6 5.f3 exf3 6.Nxf3 Bf5, I think Stefan Bucker's suggestion of 7.Bg5, with the idea 7...e6 8.Nh4, and meeting other moves with Qe2 and 0-0-0, looks good enough for dynamic equality.
My response is as follows.
A) 18 Nd6 Qd5! =+
B) 12 Qh4 h6 13 Bf6 Bf6 14 Ne4! f5! 15 Nf6+
14 Rxf6! Bxf6 15 Qxf6 with White counterplay.
14...Qe5 15 Raf1 Bd7 16 Ne4 000 17 Qf2 Bf6 18 Nxf6 Kb8 19 Re1 Qd6 =+
C) 10 Qe1 is indeed good, and apparently Peter Leisebein has played it with success. However, I will have to look into my collection of ZG games to locate these. In the line you give, I think that 10 Qe1 Nxf3 11 Rxf3 Nd5 12 Bd3 could be tried, but 12...Nb4! looks strong for Black. Therefore, after 12 Bxe7 Qxe7 13 Qg3 is an alternative.
I think that 10 Qe1? allows too many pieces to be traded, and this must be avoided. Therefore, I would stick with line B) as outlined above.